111 lines
3.5 KiB
C
111 lines
3.5 KiB
C
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[env:megaatmega2560]
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platform = atmelavr
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board = megaatmega2560
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framework = arduino
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#include "led.h"
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#include "delay.h"
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#include "sys.h"
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#include "usart.h"
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#include "lcd.h"
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#include "key.h"
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#include "ads1115.h"
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float aa;
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int main(void)
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{
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float t1;
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u16 t,result;
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u8 key;
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u16 i=0;
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NVIC_PriorityGroupConfig(NVIC_PriorityGroup_2);// Set interrupt priority group 2
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delay_init();
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uart_init(9600); // The serial port is initialized to 9600
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LED_Init();
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//LCD_Init();
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KEY_Init();
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//IIC初始化
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ADS1115_Init();
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while(1)
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{
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key=KEY_Scan(0);
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if(key==WKUP_PRES)
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{
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result=lvbo(0xeb,0x82); // A0 A1 is the differential input test terminal, low eight bits + high eight bits 1111 1011, 1000 0010
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if(result >= 0x8000 && result <= 0xffff)
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result = 0xffff - result; //If the difference is negative, take the absolute value, so that A0 and A1 can be connected positively and negatively.
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else if(result >= 0xffff)
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result = 0;
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t1=4.096*2*result/65535; //converted to voltage
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printf("The range is 4.096V, the voltage between A0-A1 = %f V\r\n",t1);//print
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if(result == 0x7fff || result == 0x8000)
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{
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printf("over range \r\n\r\n");
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}
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else
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{
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printf("Read OK \r\n\r\n");
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}
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}
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if(key==KEY0_PRES)
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{
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result=lvbo(0xe3,0xb2); //A2 A3 is the differential input test terminal, low eight bits + high eight bits 1111 0011,1011 0010
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if(result >= 0x8000)
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result = 0xffff - result; //If the difference is negative, take the absolute value, so that A2 and A3 can be connected positively and negatively.
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t1=4.096*2*result/65535; //converted to voltage
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printf("The range is 4.096V, the voltage between A2-A3 = %f V\r\n",t1); //print
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if(result == 0x7fff || result == 0x8000) // exceeds the maximum value or falls below the minimum value
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{
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printf("over range \r\n\r\n");
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}
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else
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{
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printf("over range\r\n\r\n");
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}
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}
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if(key == KEY1_PRES)
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{
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result=lvbo(0xe3,0xb4); //A2 A3 is the differential input test terminal, low eight bits + high eight bits 1111 0011,1011 0100
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if((result >= 0x8000) && (result <= 0xffff))
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result = 0xffff - result; //If the difference is negative, take the absolute value, so that A0 and A1 can be connected positively and negatively.
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else if(result >= 0xffff)
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result = 0;
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t1=2.048*2*result/65535; //converted to voltage
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printf("The range is 2.048V, the voltage between A0-A1 = %f V\r\n",t1);//打印
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if(result == 0x7fff || result == 0x8000)
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{
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printf("over range \r\n\r\n");
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}
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else
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{
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printf("over range \r\n\r\n");
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}
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}
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i++;
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delay_ms(10);
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if(i==20)
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{
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LED0=!LED0;//Prompt system is running
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i=0;
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}
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}
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}
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